mirror of
https://github.com/fofolee/uTools-Manuals.git
synced 2025-06-06 21:44:03 +08:00
修正
This commit is contained in:
parent
47f6520815
commit
18c5b121fb
@ -1170,7 +1170,7 @@
|
||||
<p><code class="docutils literal"><span class="pre">find_parent()</span></code> 和 <code class="docutils literal"><span class="pre">find_parents()</span></code> 方法会让人联想到 <a class="reference internal" href="#parent">.parent</a> 和 <a class="reference internal" href="#parents">.parents</a> 属性.它们之间的联系非常紧密.搜索父辈节点的方法实际上就是对 <code class="docutils literal"><span class="pre">.parents</span></code> 属性的迭代搜索.</p>
|
||||
</div>
|
||||
<div class="section" id="find-next-siblings-find-next-sibling">
|
||||
<h2>find_next_siblings() 合 find_next_sibling()<a class="headerlink" href="#find-next-siblings-find-next-sibling" title="永久链接至标题"></a></h2>
|
||||
<h2>find_next_siblings() 和 find_next_sibling()<a class="headerlink" href="#find-next-siblings-find-next-sibling" title="永久链接至标题"></a></h2>
|
||||
<p>find_next_siblings( <a class="reference internal" href="#id35">name</a> , <a class="reference internal" href="#css">attrs</a> , <a class="reference internal" href="#recursive">recursive</a> , <a class="reference internal" href="#id36">string</a> , <a class="reference internal" href="#keyword">**kwargs</a> )</p>
|
||||
<p>find_next_sibling( <a class="reference internal" href="#id35">name</a> , <a class="reference internal" href="#css">attrs</a> , <a class="reference internal" href="#recursive">recursive</a> , <a class="reference internal" href="#id36">string</a> , <a class="reference internal" href="#keyword">**kwargs</a> )</p>
|
||||
<p>这2个方法通过 <a class="reference internal" href="#next-siblings-previous-siblings">.next_siblings</a> 属性对当tag的所有后面解析 <a class="footnote-reference" href="#id92" id="id37">[5]</a> 的兄弟tag节点进行迭代, <code class="docutils literal"><span class="pre">find_next_siblings()</span></code> 方法返回所有符合条件的后面的兄弟节点, <code class="docutils literal"><span class="pre">find_next_sibling()</span></code> 只返回符合条件的后面的第一个tag节点.</p>
|
||||
|
Loading…
x
Reference in New Issue
Block a user